Can you WRT54G to WRT54G to WRT54G to WRT54G?

Discussion in 'DD-WRT Firmware' started by dunb440, Sep 1, 2005.

  1. dunb440

    dunb440 Network Guru Member

    :drinking: Maybe a stupid qwestion, but can you have 1 to the other to the other, basically extending the range? like one every 100' and at the end be 400 feet away with a strong signal?
  2. aaaaaa

    aaaaaa Network Guru Member

    Yes, this is what WDS bridging is all about. I have 4 units WDS bridged to cover my house. They are not bridged in a straight line (chain), though you can do it that way. The optimal way is a star pattern. For example,

    rather than A--B--C--D. The latter will work; however, the further along the WDS chain your wireless client gets, the lower its maximum throughput will be.
  3. dunb440

    dunb440 Network Guru Member

    Do you know about how much throughput will be lost in 300'?
    or how many bms I'll wind up with?
  4. kc7aad

    kc7aad Guest

    After the second one, it pretty much cuts the next in half, and the one after that in half agin..
  5. littlewhoo

    littlewhoo Network Guru Member

    Ususally with 802.11g you get a gross data rate of at most ~27 MBit/s.
    In a WDS chain of 4 routers you can expect at most 6-7 MBit/s. If there are obstacles between the routers or if there is more than one client connected to the WDS chain, the data rate is much lower. So in most cases it will be more like 1-3 MBit/s.
  6. 4Access

    4Access Network Guru Member

    Here's some examples to elaborate a little more on what kc7aad & littlewhoo said:

    The basic principal for calculating the throughput speed over a WDS connection is to divide the starting bandwidth (24Mbps is what I usually use based on the reviews I've read at in half for each additional wireless hop after the 1st one.

    Red = Wireless Hop
    Green = Wired connection
    STA = Wireless Client

    STA ~~ 1 ~~ WRT-4 ~~ 2 ~~ WRT-3 ~~ 3 ~~ WRT-2 ~~ 4 ~~ WRT-1 == Internet

    For the above example divide 24Mbps in half 3 times to get a total net throughput of 3Mbps for a single client under optimal conditions.

    Another possibility:
    STA ~~ 1 ~~ WRT-4 ~~ 2 ~~ WRT-3 ~~ 3 ~~ WRT-2 ~~ 4 ~~ WRT-1 ~~ 5 ~~ STA

    In this case there is an additional wireless hop which puts the throughput between the two wireless clients at about 1.5Mbps under optimal conditions. (And remember that this is a half-duplex connection.)

    Little more info: here
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